CUET CUET General Test 2024 - If the mean of 3, 4, 9, 2k, 10, 8, 6 and (k + 6) is 8, and mode of 2, 2, 3, 2p, (2p + 1), 4, 4, 5 and 6 is 4 (p is a natural number), then the value of (k - 2p) is: | PYQs + Solutions | AfterBoards
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CUET General Test 2024 PYQs

CUET General Test 2024

Arithmetic
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Central Tendency

Medium

If the mean of 3,4,9,2k,10,8,63, 4, 9, 2k, 10, 8, 6 and (k+6)(k + 6) is 88, and mode of 2,2,3,2p,(2p+1),4,4,52, 2, 3, 2p, (2p + 1), 4, 4, 5 and 66 is 44 (p is a natural number), then the value of (k2p)(k - 2p) is:

Correct Option: 3
Mean =3+4+9+2k+10+8+6+(k+6)8=8= \dfrac{3+4+9+2k+10+8+6+(k+6)}{8}=8
46+3k=64\Rightarrow 46+3k = 64 \newline 3k=18k=6\Rightarrow 3k = 18 \rightarrow k = 6
If 44 is the mode then 44 must have the maximum frequency in the given series.
This means that either 2p2p or 2p+12p+1 must be equal to 4. \newline Also, the question mentions that pp is a natural number so 2p+12p+1 can't be equal to 4.
2p=4p=2\therefore 2p = 4 \rightarrow p=2
(k2p)=64=2(k-2p) = 6-4=2

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