IPMAT Indore 2019 (SA) - A real-valued function f satisfies the relation f(x)f(y) = f(2xy + 3) + 3f(x + y) - 3f(y) + 6y, for all real numbers x and y, then the value of f(8) is | PYQs + Solutions | AfterBoards
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IPMAT Indore 2019

Algebra
>
Functions

Hard

A real-valued function ff satisfies the relation f(x)f(y)=f(2xy+3)+3f(x+y)−3f(y)+6yf(x)f(y) = f(2xy + 3) + 3f(x + y) - 3f(y) + 6y, for all real numbers xx and yy, then the value of f(8)f(8) is

Entered answer:

Correct Answer: 19

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Suppose that a real-valued function f(x)f(x) of real numbers satisfies f(x+xy)=f(x)+f(xyf(x + xy) = f(x) + f(xy) for all real x,y,x, y, and that f(2020)=1f(2020) = 1. Compute f(2021)f(2021).

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