IPMAT Indore 2021 (MCQ) - In a city, 50% of the population can speak in exactly one language among Hindi, English and Tamil, while 40% of the population can speak in at least two of these three languages. Moreover, the number of people who cannot speak in any of these three languages is twice the number of people who can speak in all these three languages. If 52% of the population can speak in Hindi and 25% of the population can speak exactly in one language among English and Tamil, then the percentage of the population who can speak in Hindi and in exactly one more language among English and Tamil is | PYQs + Solutions | AfterBoards
Skip to main contentSkip to question navigationSkip to solution
IPMAT Indore Free Mocks Topic Tests

IPMAT Indore 2021 (MCQ) PYQs

View all IPMAT/JIPMAT PYQs →
Collection of AfterBoards IPMAT JIPMAT Past Year Papers with Solutions

IPMAT Indore 2021

Modern Math
>
Set Theory

Medium

In a city, 50% of the population can speak in exactly one language among Hindi, English and Tamil, while 40% of the population can speak in at least two of these three languages. Moreover, the number of people who cannot speak in any of these three languages is twice the number of people who can speak in all these three languages. If 52% of the population can speak in Hindi and 25% of the population can speak exactly in one language among English and Tamil, then the percentage of the population who can speak in Hindi and in exactly one more language among English and Tamil is

Correct Option: 1

Related questions:

IPMAT Indore 2019

In a school 70%70\% of the boys like cricket and 50%50\% like football. If x%x\% like both Cricket and Football, then

IPMAT Indore 2019

In a class of 65 students 40 like cricket, 25 like football and 20 like hockey. 10 students like both cricket and football, 8 students like football and hockey and 5 students like all three sports. If all the students like at least one sport, then the number of students who like both cricket and hockey is

IPMAT Indore 2019

Let the set P={2,3,4,...,25}P= \{2,3,4,..., 25\}. For each k∈Pk ∈ P, define Q(k)={x∈PQ(k)= \{x ∈ P such that x>kx > k and kk divides x}x\}. Then the number of elements in the set P−Uk=225Q(k)P - U_{k=2}^{25} Q(k) is

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question