IPMAT Indore 2021 (MCQ) - Total points Team F scored was | PYQs + Solutions | AfterBoards
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IPMAT Indore 2021 (MCQ) PYQs

IPMAT Indore 2021

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Hard

In a football tournament six teams A, B, C, D, E, and F participated. Every pair of teams had exactly one match among them. For any team, a win fetches 2 points, a draw fetches 1 point, and a loss fetches no points. Both teams E and F ended with less than 5 points. At the end of the tournament points table is as follows (some of the entries are not shown):
Teams Played
Wins
Losses
Draws
Points
A
5
0
8
B
5
2
6
C
5
2
5
D
5
1
5
E
5
1
F
5
It is known that: (1) team B defeated team C, and (2) team C defeated team D

Total points Team F scored was

Correct Option: 3
Teams Played
Wins
Losses
Draws
Points
A
5
3 0
2 8
B
5
3 2
0 6
C
5
2 2
1 5
D
5
1 1
3 5
E
5
1
F
5
From the given points, we can figure out from A to D how their matches went, i.e. how many they won, lost, or ended with a draw. \newline
Teams Played
Wins
Losses
Draws
Points
A
5
3 0
2 8
B
5
3 2
0 6
C
5
2 2
1 5
D
5
1 1
3 5
E
5
0 1
4 4
F
5
We know that E and F have less than 5 points each. It's given that E has one loss, so now he has 4 more matches. All 4 of these have to be draws, because that's the only case where E will have less than 5 points. Even a single win would exceed the points and contradict what's given.
Teams Played
Wins
Losses
Draws
Points
A
5
3 0
2 8
B
5
3 2
0 6
C
5
2 2
1 5
D
5
1 1
3 5
E
5
0 1
4 4
F
5
0 3 2 2
Things to note: \newline Total Number of Points =30=30, since there will be a total of 1515 matches and each match results in two points (if a team loses, the winning team gets two points and if a match ends in a draw, both teams get one point each)
Hence, E+F=6E+F=6 points \newline F=2F=2 points
F could have either 1 win, 4 losses, 0 draws or 0 wins, 3 losses, and 2 draws.
The table becomes inconsistent with the former, since no two teams can have 0 draws and B already has 0 draws.
Hence, the table above is our table.
From it, we can see that F scored 2 points.

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