IPMAT Indore 2021 (SA) - If a function f(a) = max (a, 0) then the smallest integer value of x for which the equation f(x - 3) + 2f(x + 1) = 8 holds true is _______. | PYQs + Solutions | AfterBoards
Skip to main contentSkip to question navigationSkip to solution
IPMAT Indore Free Mocks Topic Tests

IPMAT Indore 2021 (SA) PYQs

View all IPMAT/JIPMAT PYQs →
Collection of AfterBoards IPMAT JIPMAT Past Year Papers with Solutions

IPMAT Indore 2021

Algebra
>
Functions

Medium

If a function f(a)=max(a,0)f(a) = max (a, 0) then the smallest integer value of xx for which the equation f(x−3)+2f(x+1)=8f(x - 3) + 2f(x + 1) = 8 holds true is _______.

Entered answer:

Correct Answer: 3

Related questions:

IPMAT Indore 2019

The function f(x)=x3−5x2−8x3f(x) = \dfrac{x^3 - 5x^2 - 8x}{3} is

IPMAT Indore 2019

A real-valued function ff satisfies the relation f(x)f(y)=f(2xy+3)+3f(x+y)−3f(y)+6yf(x)f(y) = f(2xy + 3) + 3f(x + y) - 3f(y) + 6y, for all real numbers xx and yy, then the value of f(8)f(8) is

IPMAT Indore 2020

Given f(x)=x2+log⁡3xf(x) = x^2 + \log_3 x and g(y)=2y+f(y)g(y) = 2y + f(y), then the value of g(3)g(3) equals

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question