IPMAT Indore 2024 (MCQ) - If |x+1| + (y+2)^2 = 0 and ax - 3ay = 1, then the value of a is | PYQs + Solutions

IPMAT Indore 2024

Algebra

Modulus

Easy

If $|x+1| + (y+2)^2 = 0$ and $ax - 3ay = 1$ , then the value of $a$ is

\frac{1}{5}

\frac{1}{2}

\frac{1}{7}

Correct Option: 1

We know that a mod function will always be non-negative, and a square would also be non-negative. If the sum of both is 0, then both the terms have to equal 0.

IPMAT Indore 2024 (MCQ) PYQs

If ∣x+1∣+(y+2)2=0|x+1| + (y+2)^2 = 0∣x+1∣+(y+2)2=0 and ax−3ay=1ax - 3ay = 1ax−3ay=1, then the value of aaa is

Keyboard Shortcuts

If $|x+1| + (y+2)^2 = 0$ and $ax - 3ay = 1$ , then the value of $a$ is