IPMAT Indore 2024 (SA) - Let f and g be two functions defined by f(x) = |x + |x|| and g(x) = 1/x for x ≠ 0. If f(a) + g(f(a)) = 13/6 for some real a, then the maximum possible value of f(g(a)) is: | PYQs + Solutions | AfterBoards
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IPMAT Indore 2024

Algebra
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Functions

Medium

Let ff and gg be two functions defined by f(x)=∣x+∣x∣∣f(x) = |x + |x|| and g(x)=1xg(x) = \frac{1}{x} for x≠0x \neq 0. If f(a)+g(f(a))=136f(a) + g(f(a)) = \frac{13}{6} for some real aa, then the maximum possible value off(g(a)) f(g(a)) is:

Entered answer:

Correct Answer: 6

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