IPMAT Rohtak 2019 (LR) - A clock is such that it loses 4 minutes each day. The clock is set right on February 25, 2008 at 2 p.m. How many minutes should be added to get the right time when the clock shows 9 am on 3rd March, 2008? | PYQs + Solutions | AfterBoards
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IPMAT Rohtak 2019 (LR) PYQs

IPMAT Rohtak 2019

Logical Reasoning
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Clocks & Calendar

Medium

A clock is such that it loses 4 minutes each day. The clock is set right on February 25, 2008 at 2 p.m. How many minutes should be added to get the right time when the clock shows 9 am on 3rd March, 2008?

Correct Option: 1
Actual time passed =(6=(6 days ×\times 2424 hours )+19)+19 hours =163=163 hours.
Given that the clock loses 44 minute in every single day.
11 day =24=24 hours =24×60=1440=24 \times 60=1440 minutes.
In 14401440 minutes, the clock losses 44 minutes.
Therefore, the minute hand moves at a slightly slower pace.
The speed of minute hand can be expressed as 14361440\frac{1436}{1440} fractional part of one minute.
Actual time elapsed is just the reciprocal of it, i.e =14401436=\frac{1440}{1436}
Thus in the given time of 163163 hours,
Actual time elapsed =163=163 (hours) ×\times 6060 (minutes) ×\times 14401436\frac{1440}{1436} (minutes hand)
But due to loss in time, the time elapsed by clock is =163×60=163 \times 60
Difference =(163×60×(14401436))(163×60)=\left(163 \times 60 \times\left(\frac{1440}{1436}\right)\right)-(163 \times 60)
=1408320014369780=9780359=\frac{14083200}{1436}-9780=\frac{9780}{359}
This difference must be added to get the right time.

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