IPMAT Indore 2023 (SA) - If f(n)= 1 + 2 + 3 +*s+(n+1) and g(n)= _k=1^k=n 1/f(k), then the least value of n for which g(n) exceeds the value 99/100 is: | PYQs + Solutions | AfterBoards
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IPMAT Indore 2023

Algebra
>
Progression & Series

Hard

If f(n)=1+2+3+⋯+(n+1)f(n)= 1 + 2 + 3 +\cdots+(n+1) and g(n)=∑k=1k=n1f(k)g(n)= \sum_{k=1}^{k=n} \dfrac{1}{f(k)}, then the least value of nn for which g(n)g(n) exceeds the value 99100\dfrac{99}{100} is:

Entered answer:

Correct Answer: 199

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