IPMAT Indore 2019 (MCQ) - If (1 + x - 2x^2)^6 = A_0 + _r=1^12 A_r x^r, then the value of A_2 + A_4 + A_6 + *s + A_12 is | PYQs + Solutions | AfterBoards
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IPMAT Indore 2019

Algebra
>
Progression & Series

Hard

If (1+x−2x2)6=A0+∑r=112Arxr(1 + x - 2x^2)^6 = A_0 + \sum_{r=1}^{12} A_r x^r, then the value of A2+A4+A6+⋯+A12A_2 + A_4 + A_6 + \cdots + A_{12} is

Correct Option: 1

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