IPMAT Indore 2019 (MCQ) - Points P, Q, R, and S are taken on sides AB, BC, CD, and DA of square ABCD respectively, so that AP/PB = BQ/QC = CR/RD = DS/SA = 1/n. Then the ratio of the area of PQRS to the area of ABCD is | PYQs + Solutions

IPMAT Indore 2019

Geometry

Quadrilaterals

Medium

Points $P$ , $Q$ , $R$ , and $S$ are taken on sides $AB$ , $BC$ , $CD$ , and $DA$ of square $ABCD$ respectively, so that $\frac{AP}{PB} = \frac{BQ}{QC} = \frac{CR}{RD} = \frac{DS}{SA} = \frac{1}{n}$ . Then the ratio of the area of $PQRS$ to the area of $ABCD$ is

1 : (1 + n)

1 : n

1 + n^2 : (1 + n)^2

(1 + n) : (1 + n^2)

Correct Option: 3