IPMAT Indore 2019 (MCQ) - Given that x + y = 1, the range of x - y is | PYQs + Solutions

IPMAT Indore 2019

Geometry

Trigonometry

Hard

Given that $\cos x + \cos y = 1$ , the range of $\sin x - \sin y$ is

[-1, 1]

[-2, 2]

[0, \sqrt{3}]

[-\sqrt{3}, \sqrt{3}]

Correct Option: 4

Related questions:

IPMAT Indore 2019

sin \theta + cos \theta = m

sin^6 \theta + cos^6 \theta

IPMAT Indore 2019

(x, y)

\sin x + \sin y = \sin(x + y)

|x| + |y| = 1

IPMAT Indore 2020

\cos^2\left(\frac{\pi}{8}\right) + \cos^2\left(\frac{3\pi}{8}\right) + \cos^2\left(\frac{5\pi}{8}\right) + \cos^2\left(\frac{7\pi}{8}\right)