JIPMAT 2023 (QA) - <p>How many proper divisors (that is, divisors other than 1 or 7200) does 7200 have?</p> | PYQs + Solutions | AfterBoards
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JIPMAT 2023 (QA) PYQs

JIPMAT 2023

Number System
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Factorisation

Easy

How many proper divisors (that is, divisors other than 1 or 7200) does 7200 have?

Correct Option: 2
To find the number of factors of a number N=pa×qb×rcN = p^{a} × q^{b} × r^{c} \newline The formula is: (a+1)(b+1)(c+1)(a+1)(b+1)(c+1) \newline where a,b,ca,b,c are powers in prime factorization and p,q,rp,q,r are prime numbers
For 7200: \newline Prime factorization = 25×32×522^5 × 3^2 × 5^2
Total number of factors: \newline (5+1)(2+1)(2+1)(5+1)(2+1)(2+1)
=6×3×3= 6 × 3 × 3
=54= 54 factors
Proper divisors exclude 1 and the number itself
Therefore, number of proper divisors = 542=5254 - 2 = 52
The answer is 52.52.

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