JIPMAT 2023 (QA) - <p>The radii of two cones are in the ratio 2:3 and their volumes are in the ratio 1:3. Then the ratio of their heights is:</p> | PYQs + Solutions | AfterBoards
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JIPMAT 2023 (QA) PYQs

JIPMAT 2023

Geometry
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Solids

Conceptual

The radii of two cones are in the ratio 2:3 and their volumes are in the ratio 1:3. Then the ratio of their heights is:

Correct Option: 3
1) Let's use the formula for volume of a cone:
V=13πr2hV = \frac{1}{3}πr^2h, where rr is radius and hh is height
2) Given:\newline - Ratio of radii (r1:r2)=2:3(r_1:r_2) = 2:3\newline - Ratio of volumes (V1:V2)=1:3(V_1:V_2) = 1:3
3) Let's express volume ratio using formula:
V1V2=13πr12h113πr22h2=r12h1r22h2=13\frac{V_1}{V_2} = \frac{\frac{1}{3}πr_1^2h_1}{\frac{1}{3}πr_2^2h_2} = \frac{r_1^2h_1}{r_2^2h_2} = \frac{1}{3}
4) Now substitute radius ratio:
If r1r2=23\frac{r_1}{r_2} = \frac{2}{3}, then r12r22=49\frac{r_1^2}{r_2^2} = \frac{4}{9}
5) Put this in volume ratio equation:
49×h1h2=13\frac{4}{9} × \frac{h_1}{h_2} = \frac{1}{3}
6) Solve for height ratio:
h1h2=13×94=34\frac{h_1}{h_2} = \frac{1}{3} × \frac{9}{4} = \frac{3}{4}
Therefore, the ratio of heights (h1:h2)=3:4(h_1:h_2) = 3:4
The answer is 3:43:4.

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