JIPMAT 2021 (QA) - The length of canvas 1.1 m wide required to build a conical tent of height 14m and the floor area 346.5 m^2 is | PYQs + Solutions | AfterBoards
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JIPMAT 2021 (QA) PYQs

JIPMAT 2021

Geometry
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Conceptual

The length of canvas 1.1 m wide required to build a conical tent of height 14m and the floor area 346.5 m2m^{2} is

Correct Option: 2
Let's solve this step by step:
Area of floor = 346.5346.5 m2m^2
Floor is circular, so using area formula: \newline 346.5=πr2346.5 = \pi r^2
Radius of floor = r=346.5π=10.5r = \sqrt{\frac{346.5}{\pi}} = 10.5 m
Height of tent = h=14h = 14 m
Slant height using Pythagoras theorem: \newline l=h2+r2=142+10.52=196+110.25=306.25=17.5l = \sqrt{h^2 + r^2} = \sqrt{14^2 + 10.5^2} = \sqrt{196 + 110.25} = \sqrt{306.25} = 17.5 m
Area of curved surface = πrl\pi r l
=π×10.5×17.5=577.5= \pi × 10.5 × 17.5 = 577.5 m2^2
Width of canvas = 1.11.1 m
Length of canvas required = 577.51.1=525\frac{577.5}{1.1} = 525 m
The answer is 525525 m.

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