CUET CUET Mathematics 2024 - If a function f(x)=x^2+b x+1 is increasing in the interval [1,2], then the least value of b is : | PYQs + Solutions | AfterBoards
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CUET Mathematics 2024

Calculus
>
Application of Derivatives

Easy

If a function f(x)=x2+bx+1f(x)=x^{2}+b x+1 is increasing in the interval [1,2][1,2], then the least value of bb is :

Correct Option: 3
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Related questions:

CUET Mathematics 2024

For the function f(x)=2x3−9x2+12x−5f(x) = 2x^3 - 9x^2 + 12x - 5, x∈[0,3]x \in [0, 3], match List-I with List-II :
List-I List-II
A. Absolute maximum value (I) 3 3
B. Absolute minimum value (II) 0 0
C. Point of maxima (III) −5 -5
D. Point of minima (IV) 4 4

CUET Mathematics 2024

f(x)=sin⁡x+12cos⁡2x in [0,π2]f(x)=\sin x+\frac{1}{2} \cos 2 x \text { in }\left[0, \frac{\pi}{2}\right]
(A) f′(x)=cos⁡x−sin⁡2xf^{\prime}(x)=\cos x-\sin 2 x
(B) The critical points of the function are x=π6x=\frac{\pi}{6} and x=π2x=\frac{\pi}{2}
(C) The minimum value of the function is 22
(D) The maximum value of the function is 34\frac{3}{4}
Choose the correct answer from the options given below :

CUET Mathematics 2024

If f(x)=2(tan⁡−1(ex)−π4)f(x)=2\left(\tan ^{-1}\left(e^{x}\right)-\frac{\pi}{4}\right), then f(x)f(x) is :

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