CUET CUET Mathematics 2024 - Three defective bulbs are mixed with 8 good ones. If three bulbs are drawn one by one with replacement, the probabilities of getting exactly 1 defective, more than 2 defective, no defective and more than 1 defective respectively are: | PYQs + Solutions

CUET Mathematics 2024

Algebra

Probability

Hard

Three defective bulbs are mixed with $8$ good ones. If three bulbs are drawn one by one with replacement, the probabilities of getting exactly $1$ defective, more than $2$ defective, no defective and more than $1$ defective respectively are:

\frac{27}{1331}, \frac{576}{1331}, \frac{243}{1331}

and

\frac{512}{1331}

\frac{27}{1331}, \frac{243}{1331}, \frac{576}{1331}

and

\frac{512}{1331}

\frac{576}{1331}, \frac{27}{1331}, \frac{512}{1331}

and

\frac{243}{1331}

\frac{243}{1331}, \frac{576}{1331}, \frac{512}{1331}

and

\frac{27}{1331}

Correct Option: 3

Will be added.

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$X$	0	1	2	otherwise
$P(X)$	$k$	$2k$	$3k$	$0$

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4

CUET Mathematics 2024