CUET CUET Mathematics 2024 - If the random variable X has the following distribution: <table class="question-table" border="1"> <thead> <tr> <th> X </th> <th>0</th> <th>1</th> <th>2</th> <th>otherwise</th> </tr> </thead> <tbody> <tr> <td> P(X) </td> <td> k </td> <td> 2k </td> <td> 3k </td> <td> 0 </td> </tr> </tbody> </table> Match List-I with List-II: <table class="question-table" border="1"> <thead> <tr> <th>List-I</th> <th>List-II</th> </tr> </thead> <tbody> <tr> <td>(A) k </td> <td>(I) 5/6 </td> </tr> <tr> <td>(B) P(X < 2) </td> <td>(II) 4/3 </td> </tr> <tr> <td>(C) E(X) </td> <td>(III) 1/2 </td> </tr> <tr> <td>(D) P(1 ≤ X ≤ 2) </td> <td>(IV) 1/6 </td> </tr> </tbody> </table> | PYQs + Solutions

CUET Mathematics 2024

Algebra

Probability

Easy

If the random variable $X$ has the following distribution:

$X$ 0 1 2 otherwise

$P(X)$ $k$ $2k$ $3k$ $0$

Match List-I with List-II:

List-I List-II

(A) $k$ (I) $\frac{5}{6}$

(B) $P(X < 2)$ (II) $\frac{4}{3}$

(C) $E(X)$ (III) $\frac{1}{2}$

(D) $P(1 \leq X \leq 2)$ (IV) $\frac{1}{6}$

$X$	0	1	2	otherwise
$P(X)$	$k$	$2k$	$3k$	$0$

(A) - (I), (B) - (II), (C) - (III), (D) - (IV)

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

(A) - (I), (B) - (II), (C) - (IV), (D) - (III)

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Correct Option: 2

Will be added.