JIPMAT 2021
Arithmetic
Time & Work
Easy
A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the beginning and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?
A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the beginning and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?
Correct Option: 2
Let's say total work = unitsInitial setup: - First 35 days: 100 men working - Last 5 days: 200 men workingAccording to work done: man-days = man-daysIf only 100 men worked: Time taken = daysSince original schedule was 40 days: Delay = daysTherefore, work would be finished 5 days behind schedule.
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