JIPMAT 2024 (QA) - A company offers four types of successive discounts A - D on the marked price of an article. Arrange these successive discounts A - D in ascending order based on the final price of the article after discounts. (A) 25 \% and 15 \% (B) 30 \% and 10 \% (C) 35 \% and 5 \% (D) 15 \% and 20 \% | PYQs + Solutions | AfterBoards
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JIPMAT 2024 (QA) PYQs

JIPMAT 2024

Arithmetic
>
Profit & Loss

Medium

A company offers four types of successive discounts A - D on the marked price of an article. Arrange these successive discounts A - D in ascending order based on the final price of the article after discounts.
(A) 25%25 \% and 15%15 \% \newline (B) 30%30 \% and 10%10 \% \newline (C) 35%35 \% and 5%5 \% \newline (D) 15%15 \% and 20%20 \%

Correct Option: 2
1) For successive discounts, we need to calculate final price after both discounts:\newline * If original price is 100100, then after two successive discounts of x%x\% and y%y\%:\newline * Final price = 100×(1x100)×(1y100)100 × (1-\frac{x}{100}) × (1-\frac{y}{100})
2) Let's calculate for each option:
A) 25%25\% and 15%15\%:\newline = 100×(10.25)×(10.15)100 × (1-0.25) × (1-0.15)\newline = 100×0.75×0.85100 × 0.75 × 0.85\newline = 63.7563.75
B) 30%30\% and 10%10\%:\newline = 100×(10.30)×(10.10)100 × (1-0.30) × (1-0.10)\newline = 100×0.70×0.90100 × 0.70 × 0.90\newline = 63.0063.00
C) 35%35\% and 5%5\%:\newline = 100×(10.35)×(10.05)100 × (1-0.35) × (1-0.05)\newline = 100×0.65×0.95100 × 0.65 × 0.95\newline = 61.7561.75
D) 15%15\% and 20%20\%:\newline = 100×(10.15)×(10.20)100 × (1-0.15) × (1-0.20)\newline = 100×0.85×0.80100 × 0.85 × 0.80\newline = 68.0068.00
3) Arranging in ascending order (lowest to highest final price):\newline C (61.7561.75) < B (63.0063.00) < A (63.7563.75) < D (68.0068.00)
Therefore, the correct order is (C), (B), (A), (D)

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