JIPMAT 2024 (QA) - The average of five consecutive numbers is a. If the next two numbers are also included, how will the average vary? | PYQs + Solutions | AfterBoards
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JIPMAT 2024 (QA) PYQs

JIPMAT 2024

Arithmetic
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Averages

Easy

The average of five consecutive numbers is a. If the next two numbers are also included, how will the average vary?

Correct Option: 1
1) Let's say first number is n. Then:\newline - First 5 numbers: n, n+1, n+2, n+3, n+4\newline - Next 2 numbers: n+5, n+6
2) First 5 numbers average = a
= n+(n+1)+(n+2)+(n+3)+(n+4)5=a\frac{n + (n+1) + (n+2) + (n+3) + (n+4)}{5} = a
= 5n+105=a\frac{5n + 10}{5} = a
= n+2=an + 2 = a
3) All 7 numbers average:
= n+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)+(n+6)7\frac{n + (n+1) + (n+2) + (n+3) + (n+4) + (n+5) + (n+6)}{7}
= 7n+217\frac{7n + 21}{7}
= n+3n + 3
4) Difference between averages:\newline = New average - Original average\newline = (n+3)(n+2)(n + 3) - (n + 2)\newline = 11
Therefore, the average will increase by 1.

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