JIPMAT 2022 (QA) - If the mean of a, b, and c is M; ab + bc + ca = 0; and the mean of a^2, b^2 and c^2 is KM^2, then K is equal to | PYQs + Solutions | AfterBoards
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JIPMAT 2022 (QA) PYQs

JIPMAT 2022

Arithmetic
>
Averages

Medium

If the mean of aa, bb, and cc is MM; ab+bc+ca=0ab + bc + ca = 0; and the mean of a2a^2, b2b^2 and c2c^2 is KM2KM^2, then KK is equal to

Correct Option: 1
From mean of aa, bb, and cc:
a+b+c3=M\frac{a + b + c}{3} = M
a+b+c=3Ma + b + c = 3M ...(1)
Given: ab+bc+ca=0ab + bc + ca = 0 ...(2)
Mean of squares:
a2+b2+c23=KM2\frac{a^2 + b^2 + c^2}{3} = KM^2
a2+b2+c2=3KM2a^2 + b^2 + c^2 = 3KM^2 ...(3)
From (1): squaring both sides \newline (a+b+c)2=9M2(a + b + c)^2 = 9M^2 \newline a2+b2+c2+2(ab+bc+ca)=9M2a^2 + b^2 + c^2 + 2(ab + bc + ca) = 9M^2
From (2): \newline a2+b2+c2=9M2a^2 + b^2 + c^2 = 9M^2
From (3): \newline 3KM2=9M23KM^2 = 9M^2 \newline K=3\boxed{K = 3}

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