JIPMAT 2022 (QA) - The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages (in years) of the son and the father are, respectively | PYQs + Solutions | AfterBoards
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JIPMAT 2022 (QA) PYQs

JIPMAT 2022

Arithmetic
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Ratio, Proportion & Variation

Easy

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages (in years) of the son and the father are, respectively

Correct Option: 1
Let son's present age = xx years \newline Then father's present age = 6x6x years
After 4 years: \newline Son's age = (x+4)(x + 4) years \newline Father's age = (6x+4)(6x + 4) years
Given that father's age will be 4 times son's age: \newline 6x+4=4(x+4)6x + 4 = 4(x + 4) \newline 6x+4=4x+166x + 4 = 4x + 16 \newline 2x=122x = 12 \newline x=6x = 6
Therefore: \newline Son's present age = 66 years \newline Father's present age = 3636 years

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