JIPMAT 2022 (QA) - The value of 325 x 325 x 325+175 x 175 x 175/325 x 325-325 x 175+175 x 175 is | PYQs + Solutions | AfterBoards
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JIPMAT 2022 (QA) PYQs

JIPMAT 2022

Algebra
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Easy

The value of 325×325×325+175×175×175325×325325×175+175×175\frac{325 \times 325 \times 325+175 \times 175 \times 175}{325 \times 325-325 \times 175+175 \times 175} is

Correct Option: 4
The given expression can be written as:
(325)3+(175)3(325)2+(175)2(325)(175)\frac{(325)^3+(175)^3}{(325)^2+(175)^2-(325)(175)}
Let a=325a=325, b=175,b=175, then:
a3+b3a2+b2ab\frac{a^3+b^3}{a^2+b^2-ab}
We know that a3+b3=(a+b)(a2+b2ab)a^3+b^3=(a+b)(a^2+b^2-ab)
So:
(a+b)(a2+b2ab)(a2+b2ab)=a+b=325+175=500\frac{(a+b)(a^2+b^2-ab)}{(a^2+b^2-ab)}=a+b=325+175=500

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