JIPMAT 2022 (QA) - If A earns 33 1/3 \% more than B, then percentage B earns less than A will be: | PYQs + Solutions

JIPMAT 2022

Arithmetic

Percentages

Easy

If A earns $33 \frac{1}{3} \%$ more than B, then percentage B earns less than A will be:

66.33%

25%

65%

33.33%

Correct Option: 2

If B's salary is

x

\newline

Then A's salary is

x + \frac{33.33}{100}x = \frac{133.33x}{100}

To find how much less B earns than A:

\frac{A-B}{A} × 100 = \frac{\frac{33.33}{100}x}{\frac{133.33}{100}x} × 100

= \frac{33.33}{133.33} × 100

= 25\%

Therefore, B earns 25% less than A.

In a simple manner so you can understand better:

\newline

If B earns

₹100

, A earns

₹133.33

\newline

Difference =

33.33

Percentage less =

\frac{33.33}{133.33} × 100 = 25\%