IPMAT Rohtak 2019 (QA) - One Trader calculates the percentage of profit on the buying price and another calculates on the selling price. When their selling prices are the same, then the difference of their actual profit is Rs 85 and both claim to have made 20% profit. What is the selling price for each? | PYQs + Solutions | AfterBoards
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IPMAT Rohtak 2019 (QA) PYQs

IPMAT Rohtak 2019

Arithmetic
>
Profit & Loss

Medium

One Trader calculates the percentage of profit on the buying price and another calculates on the selling price. When their selling prices are the same, then the difference of their actual profit is Rs 85 and both claim to have made 20% profit. What is the selling price for each?

Correct Option: 2
Let Selling Price (same for both) = xx
For First Trader (calculating on CP): \newline If CP = pp
20% profit means: x=p+20p100=1.2p20\% \text{ profit means: } x = p + \frac{20p}{100} = 1.2p
p=x1.2\therefore p = \frac{x}{1.2}
Actual profit = xx1.2=0.2x1.2=x6x - \frac{x}{1.2} = \frac{0.2x}{1.2} = \frac{x}{6}
For Second Trader (calculating on SP):
20% profit on SP means: Profit=20x100=0.2x20\% \text{ profit on SP means: Profit} = \frac{20x}{100} = 0.2x \newline If CP = qq \newline xq=0.2xx - q = 0.2x \newline q=0.8xq = 0.8x \newline Actual profit = x0.8x=0.2xx - 0.8x = 0.2x
Given that difference in profits = 8585 \newline 0.2xx6=850.2x - \frac{x}{6} = 85
6(0.2x)x6=85\frac{6(0.2x) - x}{6} = 85
1.2xx6=85\frac{1.2x - x}{6} = 85
0.2x6=85\frac{0.2x}{6} = 85
0.2x=5100.2x = 510
x=2550x = 2550
Therefore, the selling price is Rs 25502550

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