IPMAT Rohtak 2019 (QA) - The sum of third and ninth term of an A.P is 8. Find the sum of the first 11 terms of the progression. | PYQs + Solutions | AfterBoards
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IPMAT Rohtak 2019

Algebra
>
Progression & Series

Easy

The sum of third and ninth term of an A.P is 8. Find the sum of the first 11 terms of the progression.

Correct Option: 1
Third term =a+2d=a+2d \newline Ninth term =a+8d=a+8d
According to the question, \newline a+2d+a+8d=8a+2d+a+8d=8 \newline 2a+10d=82a+10d=8
We are asked to find sum of the first 11 terms.
Sn=n2[2a+(n−1)d]S_n=\frac{n}{2}[2a+(n-1)d]
S11=112[2a+10d]=112[8]=44S_{11}=\frac{11}{2}[2a+10d]=\frac{11}{2}[8]=44

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